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Clarified a comment in the mod_python docs on the status of the handler. Thanks to mattmcc for the report.

git-svn-id: http://code.djangoproject.com/svn/django/trunk@14680 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Russell Keith-Magee 2010-11-22 12:29:22 +00:00
parent cbd90455a0
commit 2596cf1652

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@ -4,10 +4,11 @@ How to use Django with Apache and mod_python
.. warning::
Support for mod_python will be deprecated in a future release of Django. If
you are configuring a new deployment, you are strongly encouraged to
consider using :doc:`mod_wsgi </howto/deployment/modwsgi>` or any of the
other :doc:`supported backends </howto/deployment/index>`.
Support for mod_python has been deprecated, and will be removed in
Django 1.5. If you are configuring a new deployment, you are
strongly encouraged to consider using :doc:`mod_wsgi
</howto/deployment/modwsgi>` or any of the other :doc:`supported
backends </howto/deployment/index>`.
.. highlight:: apache
@ -218,15 +219,15 @@ log and can even `cause response errors`_.
.. _cause response errors: http://blog.dscpl.com.au/2009/04/wsgi-and-printing-to-standard-output.html
If you have the need to print debugging information in a mod_python setup, you
If you have the need to print debugging information in a mod_python setup, you
have a few options. You can print to ``stderr`` explicitly, like so::
print >> sys.stderr, 'debug text'
sys.stderr.flush()
(note that ``stderr`` is buffered, so calling ``flush`` is necessary if you wish
debugging information to be displayed promptly.)
A more compact approach is to use an assertion::
assert False, 'debug text'