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with an instance of a derived class B would really raise an A, not a B. Since Barry fixed this anomalous behaviour, I though I might as well fix the test! (Hmm, Barry, did you not run the tests or did you miss that test_opcodes failed?)
102 lines
1.7 KiB
Python
102 lines
1.7 KiB
Python
# Python test set -- part 2, opcodes
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from test_support import *
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print '2. Opcodes'
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print 'XXX Not yet fully implemented'
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print '2.1 try inside for loop'
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n = 0
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for i in range(10):
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n = n+i
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try: 1/0
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except NameError: pass
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except ZeroDivisionError: pass
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except TypeError: pass
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try: pass
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except: pass
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try: pass
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finally: pass
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n = n+i
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if n <> 90:
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raise TestFailed, 'try inside for'
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print '2.2 raise class exceptions'
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class AClass: pass
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class BClass(AClass): pass
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class CClass: pass
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class DClass(AClass):
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def __init__(self, ignore):
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pass
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try: raise AClass()
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except: pass
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try: raise AClass()
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except AClass: pass
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try: raise BClass()
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except AClass: pass
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try: raise BClass()
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except CClass: raise TestFailed
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except: pass
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a = AClass()
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b = BClass()
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try: raise AClass, b
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except BClass, v:
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if v != b: raise TestFailed
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else: raise TestFailed
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try: raise b
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except AClass, v:
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if v != b: raise TestFailed
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# not enough arguments
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try: raise BClass, a
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except TypeError: pass
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try: raise DClass, a
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except DClass, v:
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if not isinstance(v, DClass):
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raise TestFailed
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print '2.3 comparing function objects'
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f = eval('lambda: None')
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g = eval('lambda: None')
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if f != g: raise TestFailed
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f = eval('lambda a: a')
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g = eval('lambda a: a')
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if f != g: raise TestFailed
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f = eval('lambda a=1: a')
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g = eval('lambda a=1: a')
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if f != g: raise TestFailed
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f = eval('lambda: 0')
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g = eval('lambda: 1')
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if f == g: raise TestFailed
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f = eval('lambda: None')
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g = eval('lambda a: None')
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if f == g: raise TestFailed
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f = eval('lambda a: None')
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g = eval('lambda b: None')
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if f == g: raise TestFailed
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f = eval('lambda a: None')
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g = eval('lambda a=None: None')
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if f == g: raise TestFailed
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f = eval('lambda a=0: None')
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g = eval('lambda a=1: None')
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if f == g: raise TestFailed
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