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8586991099
This should match the situation in the 1.6b1 tree.
208 lines
4.1 KiB
C
208 lines
4.1 KiB
C
/* This code implemented by cvale@netcom.com */
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#define INCL_DOSPROCESS
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#define INCL_DOSSEMAPHORES
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#include "os2.h"
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#include "limits.h"
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#include "process.h"
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long PyThread_get_thread_ident(void);
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/*
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* Initialization of the C package, should not be needed.
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*/
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static void
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PyThread__init_thread(void)
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{
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}
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/*
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* Thread support.
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*/
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int
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PyThread_start_new_thread(void (*func)(void *), void *arg)
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{
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int aThread;
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int success = 1;
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aThread = _beginthread(func,NULL,65536,arg);
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if( aThread == -1 ) {
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success = 0;
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fprintf(stderr,"aThread failed == %d",aThread);
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dprintf(("_beginthread failed. return %ld\n", errno));
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}
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return success;
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}
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long
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PyThread_get_thread_ident(void)
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{
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PPIB pib;
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PTIB tib;
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if (!initialized)
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PyThread_init_thread();
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DosGetInfoBlocks(&tib,&pib);
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return tib->tib_ptib2->tib2_ultid;
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}
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static void
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do_PyThread_exit_thread(int no_cleanup)
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{
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dprintf(("%ld: PyThread_exit_thread called\n", PyThread_get_thread_ident()));
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if (!initialized)
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if (no_cleanup)
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_exit(0);
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else
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exit(0);
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_endthread();
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}
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void
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PyThread_exit_thread(void)
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{
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do_PyThread_exit_thread(0);
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}
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void
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PyThread__exit_thread(void)
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{
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do_PyThread_exit_thread(1);
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}
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#ifndef NO_EXIT_PROG
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static void
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do_PyThread_exit_prog(int status, int no_cleanup)
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{
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dprintf(("PyThread_exit_prog(%d) called\n", status));
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if (!initialized)
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if (no_cleanup)
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_exit(status);
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else
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exit(status);
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}
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void
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PyThread_exit_prog(int status)
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{
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do_PyThread_exit_prog(status, 0);
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}
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void
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PyThread__exit_prog(int status)
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{
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do_PyThread_exit_prog(status, 1);
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}
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#endif /* NO_EXIT_PROG */
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/*
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* Lock support. It has too be implemented as semaphores.
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* I [Dag] tried to implement it with mutex but I could find a way to
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* tell whether a thread already own the lock or not.
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*/
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PyThread_type_lock
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PyThread_allocate_lock(void)
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{
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HMTX aLock;
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APIRET rc;
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dprintf(("PyThread_allocate_lock called\n"));
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if (!initialized)
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PyThread_init_thread();
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DosCreateMutexSem(NULL, /* Sem name */
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&aLock, /* the semaphore */
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0, /* shared ? */
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0); /* initial state */
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dprintf(("%ld: PyThread_allocate_lock() -> %p\n", PyThread_get_thread_ident(), aLock));
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return (PyThread_type_lock) aLock;
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}
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void
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PyThread_free_lock(PyThread_type_lock aLock)
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{
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dprintf(("%ld: PyThread_free_lock(%p) called\n", PyThread_get_thread_ident(),aLock));
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DosCloseMutexSem((HMTX)aLock);
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}
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/*
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* Return 1 on success if the lock was acquired
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*
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* and 0 if the lock was not acquired. This means a 0 is returned
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* if the lock has already been acquired by this thread!
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*/
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int
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PyThread_acquire_lock(PyThread_type_lock aLock, int waitflag)
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{
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int success = 1;
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ULONG rc, count;
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PID pid = 0;
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TID tid = 0;
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dprintf(("%ld: PyThread_acquire_lock(%p, %d) called\n", PyThread_get_thread_ident(),
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aLock, waitflag));
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DosQueryMutexSem((HMTX)aLock,&pid,&tid,&count);
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if( tid == PyThread_get_thread_ident() ) { /* if we own this lock */
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success = 0;
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} else {
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rc = DosRequestMutexSem((HMTX) aLock,
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(waitflag == 1 ? SEM_INDEFINITE_WAIT : 0));
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if( rc != 0) {
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success = 0; /* We failed */
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}
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}
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dprintf(("%ld: PyThread_acquire_lock(%p, %d) -> %d\n",
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PyThread_get_thread_ident(),aLock, waitflag, success));
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return success;
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}
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void
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PyThread_release_lock(PyThread_type_lock aLock)
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{
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dprintf(("%ld: PyThread_release_lock(%p) called\n", PyThread_get_thread_ident(),aLock));
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if ( DosReleaseMutexSem( (HMTX) aLock ) != 0 ) {
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dprintf(("%ld: Could not PyThread_release_lock(%p) error: %l\n",
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PyThread_get_thread_ident(), aLock, GetLastError()));
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}
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}
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/*
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* Semaphore support.
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*/
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PyThread_type_sema
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PyThread_allocate_sema(int value)
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{
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return (PyThread_type_sema) 0;
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}
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void
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PyThread_free_sema(PyThread_type_sema aSemaphore)
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{
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}
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int
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PyThread_down_sema(PyThread_type_sema aSemaphore, int waitflag)
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{
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return -1;
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}
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void
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PyThread_up_sema(PyThread_type_sema aSemaphore)
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{
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dprintf(("%ld: PyThread_up_sema(%p)\n", PyThread_get_thread_ident(), aSemaphore));
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}
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