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cpython/Lib/code.py
Guido van Rossum 1557a7314c Checking in new module code.py -- utilities dealing with code objects.
Currently, contains one function: compile_command(), which helps
determining whether a source string is complete, incomplete or in
error.  This is useful when writing your own version of the Python
read-eval-print loop.
1997-07-18 16:57:52 +00:00

53 lines
1.5 KiB
Python

"""Utilities dealing with code objects."""
def compile_command(source, filename="<input>", symbol="single"):
r"""Compile a command and determine whether it is incomplete.
Arguments:
source -- the source string; may contain \n characters
filename -- optional filename from which source was read; default "<input>"
symbol -- optional grammar start symbol; "single" (default) or "eval"
Return value / exception raised:
- Return a code object if the command is complete and valid
- Return None if the command is incomplete
- Raise SyntaxError if the command is a syntax error
Approach:
Compile three times: as is, with \n, and with \n\n appended. If
it compiles as is, it's complete. If it compiles with one \n
appended, we expect more. If it doesn't compile either way, we
compare the error we get when compiling with \n or \n\n appended.
If the errors are the same, the code is broken. But if the errors
are different, we expect more. Not intuitive; not even guaranteed
to hold in future releases; but this matches the compiler's
behavior in Python 1.4 and 1.5.
"""
err = err1 = err2 = None
code = code1 = code2 = None
try:
code = compile(source, filename, symbol)
except SyntaxError, err:
pass
try:
code1 = compile(source + "\n", filename, symbol)
except SyntaxError, err1:
pass
try:
code2 = compile(source + "\n\n", filename, symbol)
except SyntaxError, err2:
pass
if code:
return code
if not code1 and err1 == err2:
raise SyntaxError, err1