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cpython/Tools/freeze/checkextensions.py
Guido van Rossum 4a114313a8 After variable expansion, what was formerly a single word can now
contain multiple words, all of which may have to be joined with the
path of the extension directory.
(Sjoerd)
1998-05-06 14:38:30 +00:00

91 lines
2.0 KiB
Python

# Check for a module in a set of extension directories.
# An extension directory should contain a Setup file
# and one or more .o files or a lib.a file.
import os
import string
import parsesetup
def checkextensions(unknown, extensions):
files = []
modules = []
edict = {}
for e in extensions:
setup = os.path.join(e, 'Setup')
liba = os.path.join(e, 'lib.a')
if not os.path.isfile(liba):
liba = None
edict[e] = parsesetup.getsetupinfo(setup), liba
for mod in unknown:
for e in extensions:
(mods, vars), liba = edict[e]
if not mods.has_key(mod):
continue
modules.append(mod)
if liba:
# If we find a lib.a, use it, ignore the
# .o files, and use *all* libraries for
# *all* modules in the Setup file
if liba in files:
break
files.append(liba)
for m in mods.keys():
files = files + select(e, mods, vars,
m, 1)
break
files = files + select(e, mods, vars, mod, 0)
break
return files, modules
def select(e, mods, vars, mod, skipofiles):
files = []
for w in mods[mod]:
w = treatword(w)
if not w:
continue
w = expandvars(w, vars)
for w in string.split(w):
if skipofiles and w[-2:] == '.o':
continue
if w[0] != '-' and w[-2:] in ('.o', '.a'):
w = os.path.join(e, w)
if w[:2] in ('-L', '-R'):
w = w[:2] + os.path.join(e, w[2:])
files.append(w)
return files
cc_flags = ['-I', '-D', '-U']
cc_exts = ['.c', '.C', '.cc', '.c++']
def treatword(w):
if w[:2] in cc_flags:
return None
if w[:1] == '-':
return w # Assume loader flag
head, tail = os.path.split(w)
base, ext = os.path.splitext(tail)
if ext in cc_exts:
tail = base + '.o'
w = os.path.join(head, tail)
return w
def expandvars(str, vars):
i = 0
while i < len(str):
i = k = string.find(str, '$', i)
if i < 0:
break
i = i+1
var = str[i:i+1]
i = i+1
if var == '(':
j = string.find(str, ')', i)
if j < 0:
break
var = str[i:j]
i = j+1
if vars.has_key(var):
str = str[:k] + vars[var] + str[i:]
i = k
return str