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90 lines
1.9 KiB
Python
90 lines
1.9 KiB
Python
"""Add a 'PYC ' resource named "__main__" to a resource file.
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This first puts up a dialog asking for a Python source file ('TEXT'),
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then one asking for an existing destination file ('APPL' or 'rsrc').
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It compiles the Python source into a code object, marshals it into a string,
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prefixes the string with a .pyc header, and turns it into a resource,
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which is then written to the destination.
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If the destination already contains a resource with the same name and type,
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it is overwritten.
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"""
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import marshal
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import imp
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import macfs
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from Res import *
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# .pyc file (and 'PYC ' resource magic number)
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MAGIC = imp.get_magic()
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# Complete specification of our resource
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RESTYPE = 'PYC '
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RESID = 128
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RESNAME = '__main__'
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# OpenResFile mode parameters
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READ = 1
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WRITE = 2
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def main():
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# Ask for source text
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srcfss, ok = macfs.StandardGetFile('TEXT')
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if not ok: return
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# Read the source and compile it
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# (there's no point asking for a destination if it has a syntax error)
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filename = srcfss.as_pathname()
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fp = open(filename)
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text = fp.read()
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fp.close()
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code = compile(text, filename, "exec")
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# Ask for destination file
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dstfss, ok = macfs.StandardGetFile('APPL', 'rsrc')
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if not ok: return
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# Create the raw data for the resource from the code object
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data = marshal.dumps(code)
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del code
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data = (MAGIC + '\0\0\0\0') + data
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# Open the resource file
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fnum = FSpOpenResFile(dstfss.as_pathname(), WRITE)
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# Delete any existing resource with name __main__ or number 128
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try:
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res = Get1NamedResource(RESTYPE, RESNAME)
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res.RmveResource()
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except Error:
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pass
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try:
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res = Get1Resource(RESTYPE, RESID)
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res.RmveResource()
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except Error:
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pass
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# Create the resource and write it
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res = Resource(data)
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res.AddResource(RESTYPE, RESID, RESNAME)
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# XXX Are the following two calls needed?
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res.WriteResource()
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res.ReleaseResource()
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# Close the resource file
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CloseResFile(fnum)
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if __name__ == '__main__':
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main()
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