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06b1ab8ed0
Use a list comprehension instead of filter(), since filter() needs the itertools module which isn't available at build time.
79 lines
2.2 KiB
Python
79 lines
2.2 KiB
Python
"""Filename globbing utility."""
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import sys
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import os
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import re
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import fnmatch
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__all__ = ["glob", "iglob"]
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def glob(pathname):
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"""Return a list of paths matching a pathname pattern.
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The pattern may contain simple shell-style wildcards a la fnmatch.
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"""
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return list(iglob(pathname))
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def iglob(pathname):
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"""Return a list of paths matching a pathname pattern.
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The pattern may contain simple shell-style wildcards a la fnmatch.
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"""
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if not has_magic(pathname):
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if os.path.lexists(pathname):
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yield pathname
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return
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dirname, basename = os.path.split(pathname)
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if not dirname:
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for name in glob1(os.curdir, basename):
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yield name
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return
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if has_magic(dirname):
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dirs = iglob(dirname)
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else:
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dirs = [dirname]
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if has_magic(basename):
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glob_in_dir = glob1
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else:
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glob_in_dir = glob0
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for dirname in dirs:
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for name in glob_in_dir(dirname, basename):
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yield os.path.join(dirname, name)
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# These 2 helper functions non-recursively glob inside a literal directory.
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# They return a list of basenames. `glob1` accepts a pattern while `glob0`
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# takes a literal basename (so it only has to check for its existence).
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def glob1(dirname, pattern):
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if not dirname:
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dirname = os.curdir
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if isinstance(pattern, str) and not isinstance(dirname, str):
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dirname = str(dirname, sys.getfilesystemencoding() or
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sys.getdefaultencoding())
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try:
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names = os.listdir(dirname)
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except os.error:
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return []
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if pattern[0] != '.':
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names = [x for x in names if x[0] != '.']
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return fnmatch.filter(names, pattern)
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def glob0(dirname, basename):
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if basename == '':
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# `os.path.split()` returns an empty basename for paths ending with a
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# directory separator. 'q*x/' should match only directories.
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if os.path.isdir(dirname):
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return [basename]
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else:
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if os.path.lexists(os.path.join(dirname, basename)):
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return [basename]
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return []
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magic_check = re.compile('[*?[]')
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def has_magic(s):
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return magic_check.search(s) is not None
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