#! /usr/local/bin/python # Calculate your unbirthday count (see Alice in Wonderland). # This is defined as the number of days from your birth until today # that weren't your birthday. (The day you were born is not counted). # Leap years make it interesting. import sys import time import calendar def main(): # Note that the range checks below also check for bad types, # e.g. 3.14 or (). However syntactically invalid replies # will raise an exception. if sys.argv[1:]: year = eval(sys.argv[1]) else: year = input('In which year were you born? ') if year in range(100): print 'I\'ll assume that by', year, year = year + 1900 print 'you mean', year, 'and not the arly Christian era' elif year not in range(1850, 2000): print 'It\'s hard to believe you were born in', year return # if sys.argv[2:]: month = eval(sys.argv[2]) else: month = input('And in which month? (1-12) ') if month not in range(1, 13): print 'There is no month numbered', month return # if sys.argv[3:]: day = eval(sys.argv[3]) else: day = input('And on what day of that month? (1-31) ') if month == 2 and calendar.isleap(year): maxday = 29 else: maxday = calendar.mdays[month] if day not in range(1, maxday+1): print 'There are no', day, 'days in that month!' return # bdaytuple = (year, month, day) bdaydate = mkdate(bdaytuple) print 'You were born on', format(bdaytuple) # todaytuple = time.localtime(time.time())[:3] todaydate = mkdate(todaytuple) print 'Today is', format(todaytuple) # if bdaytuple > todaytuple: print 'You are a time traveler. Go back to the future!' return # if bdaytuple == todaytuple: print 'You were born today. Have a nice life!' return # days = todaydate - bdaydate print 'You have lived', days, 'days' # age = 0 for y in range(year, todaytuple[0] + 1): if bdaytuple < (y, month, day) <= todaytuple: age = age + 1 # print 'You are', age, 'years old' # if todaytuple[1:] == bdaytuple[1:]: print 'Congratulations! Today is your', nth(age), 'birthday' print 'Yesterday was your', else: print 'Today is your', print nth(days - age), 'unbirthday' def format((year, month, day)): return '%d %s %d' % (day, calendar.month_name[month], year) def nth(n): if n == 1: return '1st' if n == 2: return '2nd' if n == 3: return '3rd' return '%dth' % n def mkdate((year, month, day)): # Januari 1st, in 0 A.D. is arbitrarily defined to be day 1, # even though that day never actually existed and the calendar # was different then... days = year*365 # years, roughly days = days + (year+3)/4 # plus leap years, roughly days = days - (year+99)/100 # minus non-leap years every century days = days + (year+399)/400 # plus leap years every 4 centirues for i in range(1, month): if i == 2 and calendar.isleap(year): days = days + 29 else: days = days + calendar.mdays[i] days = days + day return days main()